-[x-3(y-1)]+2x=3

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Solution for -[x-3(y-1)]+2x=3 equation:


Simplifying
-1[x + -3(y + -1)] + 2x = 3

Reorder the terms:
-1[x + -3(-1 + y)] + 2x = 3
-1[x + (-1 * -3 + y * -3)] + 2x = 3
-1[x + (3 + -3y)] + 2x = 3

Reorder the terms:
-1[3 + x + -3y] + 2x = 3
[3 * -1 + x * -1 + -3y * -1] + 2x = 3
[-3 + -1x + 3y] + 2x = 3

Reorder the terms:
-3 + -1x + 2x + 3y = 3

Combine like terms: -1x + 2x = 1x
-3 + 1x + 3y = 3

Solving
-3 + 1x + 3y = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 1x + 3 + 3y = 3 + 3

Reorder the terms:
-3 + 3 + 1x + 3y = 3 + 3

Combine like terms: -3 + 3 = 0
0 + 1x + 3y = 3 + 3
1x + 3y = 3 + 3

Combine like terms: 3 + 3 = 6
1x + 3y = 6

Add '-3y' to each side of the equation.
1x + 3y + -3y = 6 + -3y

Combine like terms: 3y + -3y = 0
1x + 0 = 6 + -3y
1x = 6 + -3y

Divide each side by '1'.
x = 6 + -3y

Simplifying
x = 6 + -3y

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